IC28 Mock Test Sample 16

This section explains nominal and effective rates of interest and discount, along with their mathematical relationships. It covers present value and accumulated value calculations under nominal discount rates convertible multiple times a year. Important formulas connect effective discount rates, nominal discount rates, and nominal interest rates. The chapter also discusses banker’s discount, effective annual yield, and accumulation factors under different compounding frequencies. Examples show how to calculate present values, equivalent discount rates, and accumulated values using quarterly, half-yearly, and yearly compounding. These concepts are widely applied in banking, actuarial science, investment analysis, and financial mathematics.

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Q1. The effective rate of discount per period of 1/m1/mth of a year is:

a) d(m)d^{(m)}
b) d(m)/md^{(m)}/m
c) d/md/m
d) 1d(m)1-d^{(m)}


Q2. The present value of 1 payable at the end of 1/m1/mth of a year is:

a) 1d(m)/m1-d^{(m)}/m
b) 1/(1+d(m)/m)1/(1+d^{(m)}/m)
c) (1d(m))1/m(1-d^{(m)})^{1/m}
d) 1d(m)1-d^{(m)}


Q3. The present value of 1 payable at the end of one year is:

a) (1d(m)/m)m(1-d^{(m)}/m)^m
b) 1d(m)1-d^{(m)}
c) (1+d(m))1(1+d^{(m)})^{-1}
d) (1d/m)m(1-d/m)^m


Q4. Per relation (5.1), the effective rate of discount dd is:

a) d=1(1d(m)/m)md = 1-(1-d^{(m)}/m)^m
b) d=d(m)/md = d^{(m)}/m
c) d=(1+d(m))m1d=(1+d^{(m)})^m-1
d) d=md(m)d=m \cdot d^{(m)}


Q5. Per relation (5.2), d(m)d^{(m)} in terms of effective dd is:

a) d(m)=m[1(1d)1/m]d^{(m)} = m[1-(1-d)^{1/m}]
b) d(m)=mdd^{(m)} = m \cdot d
c) d(m)=(1d)md^{(m)}=(1-d)^m
d) d(m)=1(1d)md^{(m)}=1-(1-d)^m


Q6. Since 1d=v1-d=v, relation (5.3) gives:

a) m(1v1/m)m(1-v^{1/m})
b) 1vm1-v^m
c) mv1/mmv^{1/m}
d) mvmv


Q7. Per relation (5.4), the relationship between d(m)d^{(m)} and i(m)i^{(m)} is:

a) d(m)=i(m)1+i(m)/md^{(m)}=\frac{i^{(m)}}{1+i^{(m)}/m}
b) d(m)=i(m)d^{(m)}=i^{(m)}
c) d(m)=1/i(m)d^{(m)}=1/i^{(m)}
d) d(m)=i(m)md^{(m)}=i^{(m)}-m


Q8. Per relation (5.5), i(m)i^{(m)} in terms of d(m)d^{(m)} is:

a) i(m)=d(m)1d(m)/mi^{(m)}=\frac{d^{(m)}}{1-d^{(m)}/m}
b) i(m)=d(m)i^{(m)}=d^{(m)}
c) i(m)=md(m)i^{(m)}=m \cdot d^{(m)}
d) (1+d(m)/m)m(1+d^{(m)}/m)^m


Q9. Per relation (5.6), i(m)d(m)i^{(m)}-d^{(m)} equals:

a) i(m)d(m)m\frac{i^{(m)}d^{(m)}}{m}
b) idid
c) 0
d) 1/m1/m


Q10. Accumulated value of 1 at effective interest rate ii for n years is:

a) (1+i)n(1+i)^n
b) vnv^n
c) (1d)n(1-d)^n
d) 1+ni1+ni


Q11. Accumulated value of 1 at effective discount rate dd is:

a) (1d)n(1-d)^{-n}
b) (1+d)n(1+d)^n
c) vnv^n
d) 1nd1-nd


Q12. Present value of 1 due at end of n years at effective discount dd is:

a) (1d)n(1-d)^n
b) (1d)n(1-d)^{-n}
c) 1+nd1+nd
d) vnv^n


Q13. Accumulated value at nominal rate i(m)i^{(m)} over n years equals:

a) (1+i(m)/m)mn(1+i^{(m)}/m)^{mn}
b) (1+i(m))n(1+i^{(m)})^n
c) (1i(m)/m)mn(1-i^{(m)}/m)^{mn}
d) 1+ni(m)1+ni^{(m)}


Q14. Present value at nominal discount rate d(m)d^{(m)} over n years is:

a) (1d(m)/m)mn(1-d^{(m)}/m)^{mn}
b) (1+d(m)/m)mn(1+d^{(m)}/m)^{-mn}
c) (1d(m))n(1-d^{(m)})^n
d) 1nd(m)1-nd^{(m)}


Q15. In Example 1, the nominal discount rate d(4)d^{(4)} is approximately:

a) 0.10
b) 0.36364 or 36.36%
c) 0.40
d) 0.42


Q16. In Example 2(a), equivalent effective discount rate dd is:

a) 12%
b) 11.47%
c) 12.96%
d) 10%


Q17. In Example 2(a), the corresponding effective interest rate ii is:

a) 12%
b) 12.96%
c) 11.47%
d) 10%


Q18. In Example 2(b), the effective rate of discount dd is:

a) 12%
b) 11.64%
c) 11.47%
d) 13.17%


Q19. Banker’s discount on shorter bills realizes:

a) Higher effective rate
b) Lower effective rate
c) Same rate
d) Cannot say


Q20. In Example 3, present value of Rs. 1000 due at end of 15 years is approximately:

a) Rs. 200
b) Rs. 293.86
c) Rs. 350
d) Rs. 400

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